Answer:
So a point is (-3,-5) and the vertex is (-4,-3)
Step-by-step explanation:
This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.
The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)
I will choice -3. This gives -2(-3+4)^2-3
f(-3)=-2(1)^2-3
f(-3)=-2-3
f(-3)=-5
So a point is (-3,-5) and the vertex is (-4,-3)
Answer: 78
Step-by-step explanation: typed it into a calculator
Hello!
Answer:

To solve, we will need to use Right-Triangle Trigonometry:
Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)
tan ∠S = a / (1/2b)
tan ∠S = 3√5 / 14
tan ∠S ≈ 0.479
arctan 0.479 = m∠S (inverse)
m∠S and m∠R ≈ 25.6°
Use cosine to solve for the hypotenuse, or the missing side-length:
cos ∠S = 14 / x
x · cos (25.6) = 14
x = 14 / cos(25.6)
x ≈ 15.52
Both triangles are congruent, so we can go ahead and find the perimeter of the figure:
RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.
Hope this helped you! :)
Answer:
2/8, 4,16
Step-by-step explanation: