5 and 6/7 equals 5 and 12/14 and 11/2 is 5 and 7/14 and if you subtract, you get 5/14.
<h3>Answer:</h3>
y = -3(x -2)² -5
<h3>Explanation:</h3>
The equation of a parabola with vertex (h, k) is given by ...
... y = a(x -h)² +k . . . . . . . for some vertical scale factor "a".
We can find the value of "a" by substituting the coordinates of a point that is not the vertex. Here, that point is the y-intercept: (0, -17).
... y = a(x -2)² -5 . . . . . initial form of the equation for the parabola
... -17 = a(-2)² -5 . . . . . substitute y-intercept values
... -12 = 4a . . . . . . . . . . add 5, simplify
... -12/4 = a = -3
The desired equation is ... y = -3(x -2)² -5.
Answer D because you want to get the x by itself and in order to do this she needs to multiply by -4 so that one side only has x.
Supposing you know about the derivative, notice that
![\displaystyle\lim_{h\to0}\frac{\ln(x+h)-\ln x}h=\dfrac{\mathrm d(\ln x)}{\mathrm dx}=\dfrac1x](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bh%5Cto0%7D%5Cfrac%7B%5Cln%28x%2Bh%29-%5Cln%20x%7Dh%3D%5Cdfrac%7B%5Cmathrm%20d%28%5Cln%20x%29%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac1x)
so that when
, the limit is equal to
and the answer is A.