In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS
Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle
The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.
