<em>A) Franchise is a business model Samantha have in mind.</em>
Answer: <em>A) Franchise </em>
Explanation:
Franchise is the business model which is adopted by many business organisation for the purpose of business expansion. Where the other new business holders carry out the business using the company's procedure, brand name etc.
Under the same name and business line, the business is carried out by the new reciters and a amount of their profit is earned by the owner of the business. Here in this case Samantha is using Franchise business model.
Answer:
The Journal entries are as follows:
(i) On August 1,
Cash A/c Dr. $6,500
photography equipment A/c Dr. $33,500
To common stock $40,000
(To record the issuance of common stock for cash and photography equipment)
(ii) On August 2,
Prepaid insurance A/c Dr. $2,100
To cash $2,100
(To record the cash paid in advance for insurance)
(iii) On August 5,
Office supplies A/c Dr. $880
To cash $880
(To record the cash paid for office supplies)
(iv) On August 20,
Cash A/c Dr. $3,331
To photography fees earned $3,331
(To record the photography fees earned)
(v) On August 31,
Utilities A/c Dr. $675
To cash A/c $675
(To record the cash paid for utilities)
Answer: The _youth_ of an organizational life cycle is characterized by growth and the expansion of organizational resources.
Explanation:
Answer:
$60,000 income tax benefit
Explanation:
Since Crimson Corp. had a loss from operations and sold the asset for a loss we know that they lost money with the asset and an income tax benefit was generated. To calculate the income tax benefit we need to add both losses: $40,000 (operation) + $160,000 (sale) = $200,000 in total losses.
$200,000 x 30% = $60,000 income tax benefit
Answer:
Solution:
A.
p_x=3, G_x=\frac {100}{3}=33\frac{1}{3}p
x
=3,G
x
=
3
100
=33
3
1
p_y=5, G_y=\frac{100}{5}=20p
y
=5,G
y
=
5
100
=20
B.
100-0.25\times 100=75100−0.25×100=75
p_x=3, G_x=\frac {75}{3}=25p
x
=3,G
x
=
3
75
=25
p_y=5, G_y=\frac{75}{5}=15p
y
=5,G
y
=
5
75
=15
C.
p_x=6, G_x=\frac {100}{6}=16\frac{2}{3}p
x
=6,G
x
=
6
100
=16
3
2
D.
p_y=5, G_y=\frac{100}{4}=25p
y
=5,G
y
=
4
100
=25
2.
MU_x=68-60=8, p_x=2MU
x
=68−60=8,p
x
=2
MU_y=29-25=4, p_y-?MU
y
=29−25=4,p
y
−?
\frac {MU_x}{p_x}=\frac{MU_y}{p_y}
p
x
MU
x
=
p
y
MU
y
\frac{8}{2}=\frac {4}{p_y}
2
8
=
p
y
4
p_y=1p
y
=1
