Answer:
48
Step-by-step explanation:
The answer is not correct because on line one, it should be x/4 - 8 = 4.
On line five, (-x/4)/(-4) is not x, it is x/16!
The correct solution should be:
x/4 - 8 = 4
x/4 - 8 + 8 = 4 + 8
x/4 = 12
x = 48. ![\blacksquare](https://tex.z-dn.net/?f=%5Cblacksquare)
Answer:
Turn them over
both sides
Step-by-step explanation:
Answer:
it the same because they have the same thing it just the seconded one just has more steps.
Step-by-step explanation:
It would be A and D! hope this helps
Call this piece of the plane S. Parameterize S by the vector function
s(u, v) = u i + v j + (28 - 2u - 3v)/4 k
with 1 ≤ u ≤ 4 and 2 ≤ v ≤ 6. Take the normal vector to S to be
∂s/∂u x ∂s/∂v = 1/2 i + 3/4 j + k
which has norm √((1/2)^2 + (3/4)^2 + 1^2) = √29/4
The area of S is then
![\displaystyle\iint_S\mathrm dS=\int_1^4\int_2^6\left\|\frac{\partial\mathbf s}{\partial u}\times\frac{\partial\mathbf s}{\partial v}\right\|\,\mathrm dv\,\mathrm du=\frac{\sqrt{29}}4(4-1)(6-2)=\boxed{3\sqrt{29}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Ciint_S%5Cmathrm%20dS%3D%5Cint_1%5E4%5Cint_2%5E6%5Cleft%5C%7C%5Cfrac%7B%5Cpartial%5Cmathbf%20s%7D%7B%5Cpartial%20u%7D%5Ctimes%5Cfrac%7B%5Cpartial%5Cmathbf%20s%7D%7B%5Cpartial%20v%7D%5Cright%5C%7C%5C%2C%5Cmathrm%20dv%5C%2C%5Cmathrm%20du%3D%5Cfrac%7B%5Csqrt%7B29%7D%7D4%284-1%29%286-2%29%3D%5Cboxed%7B3%5Csqrt%7B29%7D%7D)