Answer:
b) 49.48% C, 5.19% H, 28.85% N, and 16.48% O
Explanation:
we find the mass for each element in one mole by multiplying the number of atoms in one molecule with the atomic mass
mC=8Ac=8*12=96g
mH=10AH=10*1=10g
mN=4AN=4*14=56g
mO=2AO=2*16=32g
by adding the masses together we find the molar mass of the molecule
M=mC+nH+mN+mO=96+10+56+32=194g/mole
we apply the rule of threes to find the percentage of each element
194g..96gC..10gH...56gN....32gO
100g....a...........b...........c.............d
a=(100*96)/194=49.48%C
b=(100*10)/194=5.19%H
c=(100*56)/194=28.85%N
d=(100*32)/194=16.48%O
19. For the reaction, 2S+ 30=2SO3, how many moles of so3 will be produced from 12.5 g 02 and excess S?
:
For the reaction: 2S(s) + 3O2 -> 2SO2(g) How many moles of SO3 will be produced from 2.0 mol O2 and excess S?
Answer:
<em>Hydrogen.</em>
Explanation:
You've probably seen "
" which is the formula for water. It means that there's 2 hydrogen atoms, and one oxygen atom, in one molecule of water.
<em>Hope this helps! Feel free to mark me Brainliest if you feel this helped. :)</em>
Answer:
2.02 g
Explanation:
Molality (m) is the <em>number of moles of solute dissolved in 1 kg (1000 g) of solvent- </em>that is,

<em>
</em>
Our first step is to calculate the moles of NH₃ in 475 grams of methanol, using <u>molality</u> as a conversion factor.
0.250 mol/kg × 0.475 kg = 0.119 mol
This solution contains <u>0.119 moles of NH₃</u>. Now we must convert the moles to grams, using the <u>molar mass of NH₃</u> as a conversion factor
.
17.031 g/mol × 0.119 mol = 2.02 g
Therefore, 2.02 grams of NH₃ must be dissolved in 475 grams of methanol to make a 0.250 m solution.