For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as
PD= 7.37 L
<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>
Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as
l*(v/l)*l/v
Therefore, piston displacement
PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)
PD= 7.37 L
In conclusion, piston displacement
PD= 7.37 L
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Answer:
Explanation:
<em>0.5 i go to k12 i jus took the test</em>
Answer:
The answer to your question is Argon
Explanation:
Electron configuration given 1s² 2s² 2p⁶ 3s² 3p⁶
To find the element whose electron configuration is given, we can do it by two methods.
Number 1. Sum all the exponents the result will give you the atomic number of the element.
2 + 2 + 6 + 2 + 6 = 18
The element with an atomic number of 18 is Argon.
Number 2. Look at the last terms of the electronic configuration
3s² 3p⁶
Number three indicates that this element is in the third period in the periodic table.
Sum the exponents 2 + 6 = 8
Number 8 indicates that this element is the number 8 of that period without considering the transition elements.
The element with these characteristics is Argon.
Answer: 483 mL of the cleaning solution are used to clean hospital equipment
Explanation:
The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.
Measurements > Density
Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

The density of a substance is defined as the ratio between the mass and the volume of this substance:

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.
Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.