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melamori03 [73]
3 years ago
5

True or false, In order to obey law of conservation of mass, reactions are arranged to have more atoms of reactants than product

s.
Chemistry
2 answers:
Nesterboy [21]3 years ago
8 0
False - <span>This does not </span>obey<span>the </span>law of conservation of mass<span>. ... created, amount of </span>reactant<span>(s) left over, the quantity of </span>reactants<span> required to </span>make<span> a specified quantity of </span>product. 

Semenov [28]3 years ago
7 0
Reactions are not arranged to have more atoms of reactants then products
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Which of the following is NOT an example of a molecule <br> A: H2O2<br> B:NCI3<br> C:F<br> D:O3
timama [110]

C. F because it's an atom not a molecule

6 0
3 years ago
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If 36 000 kg of full cream milk containing 4% fat is to be separated in a 6 hour period into skim milk with 0.45% fat and cream
Yuri [45]

Answer:

B=5522.33kg/h

C=478.11kg/h

Explanation:

Hi! It's a mass balance. First we have to determine the inflow.

mass flow rate = 36000kg / 6h = 6000kg / h

We define the input variable

- input flow (A) = 6000kg / h

-XgA = percentage of fat in A = 0.04

We define output variables.

- skim milk (B)

-creme (C)

-XgB = fat percentage at B = 0.0045

-XgC = percentage of fat in C = 0.45

Then we can start with the balance.

As a general rule, the mass balance is:

Input = Output

Balance sheet

1) A = B + C

Fat balance

2) A * XgA = B * XgB + C * XgC

Now we can solve.

We replace and clear B in equation 2

6000kg / h * 0.04 = B * 0.0045 + C * 0.45

B = (240kg / h) /0.045-C*0.45/0.0045

3) B = 53333.33kg / h-C * 100

We replace equation 3 in 1 and clear C

A = B + C

6000kg / h = 53333.33kg / h-C * 100 + C

C=(6000kg/h-53333.33kg/h)/(-99)

C=478.11kg/h

We replace C in equation 3 and calculate B

B = 53333.33kg / h-478.11kg/h * 100

B=5522.33kg/h

Then we have the values ​​of the outflows.

C=478.11kg/h

B=5522.33kg/h

7 0
3 years ago
you just got home from a run on a hot Atlanta afternoon. you grab a 1.00-liter bottle of water and drink three-quarters of it in
nikitadnepr [17]

Answer:

41.67 mol

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1 Litre of water = 1000g

Mole = mass / molar mass

Mass of 1 L of water = 1000 g

Molar mass of water (H2O) :

(H = 1, O = 16)

H2O = (1 * 2) + 16 = (2 + 16) = 18g/mol

Amount of water consumed = (3/4) of 1 litre

= (3/4) * 1000g

= 750g

Therefore mass of water consumed = 750g

Mole = 750g / 18g/mol

Mole of water consumed = 41.6666

= 41.67 mol

3 0
3 years ago
The transfer of energy that occurs when a force is applied over a distance is
nika2105 [10]
The transfer of energy that occurs when a force is applied over a distance is WORK.

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3 0
3 years ago
3. 2.15 x 3.1 x 100 =
jeka94

Answer:

666.5

Explanation:

Multiply 2.15 and 3.1 to get 6.665.

6.665×100≈666.5

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666.5

3 0
3 years ago
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