Answer:
92.6 g.
Explanation:
- The balanced equation is:
CaC₂ + N₂ → CaCN₂ + C.
- It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
- We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:
n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.
- We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.
∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.
<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>
- Now, we can get the grams of N₂ consumed to produce 265.0 g of CaCN₂:
∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.
Explanation:
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Answer:
2.06 × 10⁻¹⁰
Explanation:
Let's consider the solution of a generic compound AB₂.
AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)
We can relate the molar solubility (S) with the solubility product constant (Kps) using an ICE chart.
AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)
I 0 0
C +S +2S
E S 2S
The solubility product constant is:
Kps = [A²⁺] × [B⁻]² = S × (2S)² = 4 × S³ = 4 × (3.72 × 10⁻⁴)³ = 2.06 × 10⁻¹⁰
<span>Pb(NO3)2(aq) + K2SO4(aq) → PbSO4(s) + 2 KNO3(aq) is </span>
Answer:
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