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sveta [45]
3 years ago
14

Can anyone please explain to me why this is question A using the second picture?

Chemistry
2 answers:
Julli [10]3 years ago
5 0
Show the whollepage need to see all the answer
Marina86 [1]3 years ago
4 0
I think the answer is A.
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3 0
4 years ago
In a titration, 25.9 mL of 3.4 x10^-3 M Ba(OH)2 neutralized 16.6 mL of HCL solution. What is the molarity of the HCL solution?
san4es73 [151]
First, We have to write the equation for neutralization:
Ba(OH)2 + 2HCl → BaCl2 + 2H2O 
so, from the equation of neutralization, we can get the ratio between Ba(OH)2 and HCl. Ba(OH)2 : HCl = 1:2 
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So no.of moles of Ba(OH)2 = (25.9ml/1000) * 3.4x10^-3 = 8.8 x 10^-5 mol
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So when we have 1.76X10^-4 Mol in 16.6 ml (and we need to get it per liter)
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4 0
3 years ago
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