Answer:
Δs=10m
5m/s
Step-by-step explanation:
s=t²+3t +5,0<=t<=2
Let f(t)=s=t²+3t +5
The displacement of the body over the time interval from 0 to 2 is
Δs=f(2)-f(0)
Δs=(2²+3(2) +5) - (0²+3(0) +5)
Δs=10m
The average velocity of the body over the time interval from 0 to 2 is
displacement / travel time =Δs/Δt
=10 / 2
=5m/s
Answer:
Using graph for units
D=1/2(6)(9)=27 sq units
E=1/2(7)(6)=21 sq units
F=1/2(6)(8)=24 sq units
Step-by-step explanation: