Answer:
The work required to stretch a spring 12 ft beyond its natural length is 432 ft-lb
Explanation:
The work to stretch a spring is calculated using the formula:
Equation (1)
W = work in ft-lb
k = spring constant in lb/ft
x = spring deformation in ft
we clear k from the equation (1)
Equation (2)
We replace x = 2ft, W = 12 ft-lb in the equation (2)
Calculation of work required to stretch spring 12 ft
We replace k = 6 lb/ft and x = 12ft in the equation (1)
Answer: 32 centimeters is 12.5984 inches
Explanation:
Metallic bonds can occur between different elements to form alloy. In contrast to electrons that participate in both ionic and covalent bonds electrons are that participate in metallic bonds delocalize forming a sea of electrons around the positive nuclei of metals.
It is fiery because it is cooled molten magma