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scoray [572]
2 years ago
14

DaJuan has a photo that is 4 inches in width by 6 inches in length that

Mathematics
1 answer:
goldenfox [79]2 years ago
5 0

Answer:3x-x+2=4

Step-by-step explanation: source: (Too much work) srry

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A dime weighs about 1/12 ounce. Jody has 1 pound (16 ounces) of dimes. About how many dimes she has?
Ilya [14]
16 * 12  = 192 dimes should be your answer.
3 0
3 years ago
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Please help me it’s due today
balu736 [363]
The answer should be 15 times 9 equals four
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3 years ago
What is the perimeter of a rectangle which measures 300m long and 78m 60 cm wide?​
Paraphin [41]

Answer:

75720cm or 757.2m

Step-by-step explanation:

300m = 30000cm

78m & 60cm=7860cm

perimeter of rectangle = 2(length) + 2(width)

2(30000) + 2(7860) = 75720cm or 757.2m

8 0
2 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
What is the square root of -1?<br> -j.<br> -1
Sindrei [870]

Answer:

Its not a real number for the square roots of negative number

its not possible... \sqrt{-4} = -2 x -2   no...   2 x 2   no..... -2 x 2 yea but thats not square root anymore...

Step-by-step explanation:

Give me brainliest!!!

7 0
3 years ago
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