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Sergio [31]
2 years ago
12

Which number line correctly shows 1. 5 + 2. 5? A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to

1. 5 and from 1. 5 to 4. A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to 1. 5 and from 1. 5 to 3. A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to 2. 5 and from 2. 5 to 5. A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 1. 5 to 3 and from 3 to 5. 5.
Mathematics
1 answer:
Usimov [2.4K]2 years ago
6 0

So we want to see which number line shows the sum 1.5 + 2.5. We will see that the correct option is <u>"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"</u>

So the number line usually starts at 0 and goes to the first number, 1.5 in this case.

Then, it moves accordingly to the second number, 2.5 (so it will move 2.5 units to the right)

So the number line should start at 0 and move to the right until it meets 1.5 + 2.5 = 4.

From the options, the only that is correct is:

<u><em>"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"</em></u>

If you want to learn more about number lines, you can read:

brainly.com/question/10851163

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Answer:

( xo , yo , zo ) = ( 1 , 0 , 1 )

Step-by-step explanation:

Given:-

- A line passing through point (3, 1, −2) intersects and is perpendicular to line with coordinates:

                  x = −1 + t, y = −2 + t, z = −1 + t   .... t = arbitrary parameter.

Find:-

The coordinates for point of intersection.

Solution:-

- The line that passes through point (3, 1, −2) = ( a, b , c ) and an a arbitrary point on the given line have the following direction vector d2 :

                 d2 = ( x2 , y2 , z2 )

                 x2 = a - ( x ) = 3 - ( -1 + t ) = 4 - t

                 y2 = b - ( y ) = 1 - ( -2 + t ) = 3 - t

                 z2 = c - ( z )  = -2 - ( -1 + t ) = -1 - t

                d2 = (  4 - t , 3 - t , -1 - t )

- The direction vector d1 of the given line is:

                 d1 = ( x1 , y1 , z1 )

                 x1 = 1

                 y1 = 1

                 z1 = 1

                 d1 = ( 1 , 1 , 1 )

- The dot product of two orthogonal vectors is always equal to zero:

                 d1.d2 = 0

                 (  4 - t , 3 - t , -1 - t ) . ( 1 , 1 , 1 ) = 0

- Solve for parameter (t):

                 (4 - t) + (3 - t) + (-1 - t) = 0

                  6 -3t = 0

                  t = 2  

- The coordinates of the point of intersections can be evaluated by substituting the value of "t" into the given equation of line:

                 xo ( t = 2) = - 1 + 2 = 1

                 yo ( t = 2) = - 2 + 2 = 0

                 zo ( t = 2) = - 1 + 2 = 1

- The coordinates are:

                 ( xo , yo , zo ) = ( 1 , 0 , 1 )

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