What does 9/10-13/18 equal as an improper fraction 100 points

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

4 0

Answer:

$\huge \frac{8}{45}$

Step-by-step explanation:

$\frac{9}{10} - \frac{13}{18} \\ \\ = \frac{9 \times 9}{10 \times 9} - \frac{13 \times 5}{18 \times 5} \\ \\ = \frac{81}{90} - \frac{65}{90} \\ \\ = \frac{81 - 65}{90}\\ \\ = \frac{16}{90} \\ \\ = \frac{8}{45} \\$

You might be interested in

Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart,and the angle between the t

qaws [65]

Ropes are 9.63 meters ans 8.178 meters.

<u>Step-by-step explanation:</u>

Step 1 :

List all the given things

Distance between people holding ropes = 40 =(40*0.3048) meters = 12.192 meters

Angle between two ropes = 86 degrees

Angle of elevation of one rope = 42 degrees

Step 2 :

Two angles of triangle are already given so third angle can be calculated as -

Third angle = 180 - ( 86 + 42 ) = 52 degrees

Step 3 :

As we know all three angles we will apply sine rule now, which is

$\frac{a}{sine A} = \frac{b}{sine B} = \frac{c}{sine C}$

Step 4 :

By putting values, we have

$\frac{a}{sine 52} = \frac{b}{sine 42} = \frac{12.192}{sine 86}$

Step 5 : Calculating a and b

$a = 12.192 * \frac{sine 52}{sine 86}$ , $b = 12.192 * \frac{sine 42}{sine 86}$

Step 6 :

By putting values of all sine and calculating we get,

a = 9.63 meters and b = 8.178 meters

4 0

3 years ago

he probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1034

garri49 [273]

Answer:

0.0071 = 0.71% probability that the San Jose Sharks win 9 games in the upcoming month.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Sharks win, or they do not. The probability of the Sharks winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$