The value of TY is 14
Given that CD is the perpendicular bisector of XY and ST and CY = 16
We need to find the value of TY
Here M is the midpoint of ST and D is the midpoint of XY
As shown in the diagram we can say that
CT = CS =12
We can also say that ST║XY
So , ∠CST = ∠CSY
∠CTS = ∠CYX
ΔSCT = ΔXCY
SX = CS - CX
= CY - CX
We can say that MT = SM = 5
DY = DX = 7
TY = SX = 4
CY = CX = 16
ST = SM + MT
ST= 5+5
∴ ST= 10
XY = XD +DY
XY = 7+7
∴ XY = 14
Hence the value of XY is 14
Learn more about Perpendicular bisector here brainly.com/question/11006922
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Answer:
1. 2(n−3)=4n+1 2 ( n - 3 ) = 4 n + 1. Simplify 2(n−3) 2 ( n - 3 ) . 2n+2⋅−3=4n+1 2 n + 2 ⋅ - 3 = 4 n + 1
2. x 2^(x-1)=10. 2x−1=10 2 x - 1 = 10
Step-by-step explanation:
J will be -3,-2
K will be -3,-7
L will be -6,-2
First you need to find a common denominator.
20/45x + 9/45x = 87
Combine like terms.
29/ 45x = 87
Multiply both sides by 45/29
x = 3,915 / 29
x = 135
Hope this helps!