Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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What is the arithmetic mean for the following numbers,88,80,75,70,38,45,70,60,60,50
Natalija [7]
Answer:
63.6
Step-by-step explanation:
X=£fx/n
= 88+80+75+70+38+45+70+60+60+50/10
= 636/10
= 63.6
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Answer:
Step-by-step explanation:
Given the Total revenue R(x) = 2x
Cost C(x) = 0.01x²+0.3x+30 where;
x = 30 and dx/dt = 9units per day.
Rate of change of revenue dR/dt = dR/dx • dx/dt
dR/dt = 2dx/dt
dR/dt = 2(9) = $18
Rate of change of revenue with respect to time is 18dollars/day.
Rate of change of cost dC/dt = dC/dx • dx/dt
dC/dt = (0.02x+0.3)dx/dt
dC/dt at x = 30 and dx/dt = 9 will give;
dC/dt = {0.02(30)+0.3}×9
dC/dt = (0.6+0.3) × 9
dC/dt = 0.9×9
dC/dt = $8.1
Rate of change of cost with respect to time is 8.1dollars/day
Profit = Revenue - Cost
Profit = 18-8.1
Daily Profit = $9.9
PART A:
The generic equation of the line is:
y-yo = m (x-xo)
First we look for the slope of the line:
m = (y2-y1) / (x2-x1)
m = ((5000) - (6000)) / (4-3)
m = -1000
Then, we substitute any point in the generic equation:
(xo, yo) = (4, 5000)
Substituting:
y-5000 = (- 1000) (x-4)
Rewriting:
y = -1000x + 4000 + 5000
y = -1000x + 9000
The equation is:
y = -1000x + 9000
PART B:
For the price of 3.50 we have:
y = -1000 * (3.5) +9000
y = 5500
