Given that:
x² + 5x - 6 = 0
Here we see that,
→ Product of coefficient of x² and constant term = 1 × 6 = 6
→Difference of the constant term and the coefficient of x² = 6 - 1 = 5
Now the given equation can be written as,
⇛x² + 6x - 1x - 6 = 0
(Here we simply applied the correc sign and splitted the middle term in two terms)
Now let's take the common terms
⇛x(x + 6) - 1(x + 6) = 0
On grouping we get,
⇛(x - 1)(x + 6) = 0
Here either (x - 1) = 0 or (x + 6) = 0 since the product is zero so anyóne of the terms should be zero.
⇛(x - 1) = 0 or (x + 6) = 0
⇛x - 1 = 0 or x + 6 = 0
⇛x = 1 or x = -6
Here we got two solutions of the equations. This means thet are in correct form.
<u>Answer</u><u>:</u> The value of X is 1 or -6.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> Solve the following equations. X^2 + 5x + 6 = 0 (Factorise) X^2 + 7x + 11 = 0 (Use the quadratic formula)..
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