2,000
hope I could help you out :]
The domain and range of
the function f(t)=sec[((pi)t)/4] are the following:
<span>Domain: All the real
numbers except t = 2 + 4k, where k is an integer. </span>
Range: (-∞, -1] U
[1, ∞)
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
Answer:
8
Step-by-step explanation:
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
9
Step-by-step explanation:
y-11=25-3y
y + 3y = 25 + 11
4y = 36
y = 36 / 4
y = 9
Hope it will help :)