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Fed [463]
3 years ago
9

Please help with this problem

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

3x times 18

10x times 18

-7x times 25

Step-by-step explanation:

that sould be right sorry if its not

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What is the intersection of a and b if A = {1, 2, 3, 4, 5} and B = {3, 4, 5}?
trasher [3.6K]

Answer:

3 and 4

Step-by-step explanation:

since they are the numbers where the two sets meet.

#CarryOnLearning

5 0
3 years ago
Solve a, b, c, & d please & I will mark you as Brainliest.
laila [671]

Answer:

Step-by-step explanation:

a) -2x-3y=5\\-5x+3y=-40\\-7x=-35\\x=5, y=-5\\\\b)5x+6y=-14\\x-2y=10\\Considering\ equation\ 2,\\3(x-2y)=3(10)\\3x-6y=30\\Hence,\\5x+6y=-14\\3x-6y=30\\8x=16\\x=2, y=-4\\\\c) -3x+3y=21\\-x-5y=-17\\Considering\ equation\ 2,\\3(-x-5y)=3(-17)\\-3x-15y=-51\\Hence, subtracting\ both\ the\ equations\ we\ get,\\-3x+3y=21\\3x+15y=51\\18y=72\\y=4, x=-3

d) Let the cost of one group lesson be x and one private lesson be y

12x+2y=110\\10x+3y=125\\By\ multiplying\ the\ first\ equation\ with\ -1.5\ in\ this\ system\ we\ get,\\-1.5(12x+2y)=-1.5(110)\\-18x-3y=-165\\Hence,\ by\ adding\ both\ the\ equations\ we\ get,\\-18x-3y=-165\\10x+3y=125\\-8x=-40\\x=5,y=25

8 0
4 years ago
Read 2 more answers
Simplify and expression for the perimeter of the the rectangle shown.
erma4kov [3.2K]

Answer:

Step-by-step explanation:

l = 8.6 x + 3

b = 5.2

perimeter =

6 0
3 years ago
Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms i
Luden [163]

Answer:

Approximately 76.5 mg.

Step-by-step explanation:

Given,

The initial quantity of the Bismuth-210, P = 233 mg,

Also, the rate of decay per day, r = 13 %

Thus, the quantity of the Bismuth-210 after 8 days would be,

A=P(1-\frac{r}{100})^8

=233(1-\frac{13}{100})^8

=233(1-0.13)^8

=233(0.87)^8

=76.4733194697

\approx 76.5\text{ mg}

3 0
3 years ago
2+2 +2x2x7x2+13 —————————-
Rashid [163]

Answer:

73

Step-by-step explanation:

2×2×7×2=56

2+2=4

56+4+13=73

4 0
3 years ago
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