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Fed [463]
3 years ago
9

Please help with this problem

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

3x times 18

10x times 18

-7x times 25

Step-by-step explanation:

that sould be right sorry if its not

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kykrilka [37]

Answer:

Andre has the correct answer. When simplified his answer is equivalent to the original equation.

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4 years ago
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The difference of six times a number and seven results in 35.
Drupady [299]
Answer is A. add 7, and then divide by 6. Your equation would be 6x-7= 35, so first you add 7 to both sides. 6x=42, and then divide by 6. x= 7

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Work the following interest problem.
Nataliya [291]
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Method of payment: discount basis
Amount of Interest: $625
<span>Term of loan: 1 year
Solution:
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6 0
3 years ago
Tall Club International has a requirement that women must be at least 70 inches tall. Given that women have normally distributed
Marizza181 [45]

Answer:

0.0150 = 1.50% of women satisfy that height requirement.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 63.7, \sigma = 2.9

Find the percentage of women who satisfy that height requirement.

This is 1 subtracted by the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 63.7}{2.9}

Z = 2.17

Z = 2.17 has a pvalue of 0.9850

1 - 0.9850 = 0.0150

0.0150 = 1.50% of women who satisfy that height requirement.

8 0
3 years ago
Given the function f(x)= x^4+6x^3-x^2-30x+4
Romashka-Z-Leto [24]

The correct answers are a,b,e,f

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4 years ago
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