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3 years ago

Pls help pls I need help

Mathematics

1 answer:

Inessa [10]3 years ago

5 0

Answer:

A.1

Step-by-step explanation:

When substitute 1 to x... it will be -6 to -9.... -6 is larger than -9

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X^3 - 5x^2 - x + 5

Zolol [24]

Answer:

(x+1)(x-1)(x-5)

The roots are 1, -1, 5

Step-by-step explanation:

x³-5x²-x+5

(x³-5x²) - (x-5)

x²(x-5) - (x-5)

(x²-1)(x-5)

(x+1)(x-1)(x-5)

The roots are 1, -1, 5

6 0

3 years ago

Can i get help please ?

wariber [46]

Answer:

D -- the last one

Step-by-step explanation:

The formula tells you what to do.

t = 3

A0 = 25

A(t) = ?

A(3) = 25 * (1/2)^3

A(t) = 25 * 1/8

A(t) = 25/8

A(t) = 3.125

4 0

3 years ago

>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

MAXImum [283]

Answer:

ohk interesting! indeed

8 0

4 years ago

18h=252 what is it???

Nadusha1986 [10]

Answer:

h=14

Step-by-step explanation:

18h=252

18h/18=252/18

h=14

5 0

3 years ago

Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.

ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: $u_{x x}+u_{y y}=0$

We must determine whether a given function is the solution to a given Laplace equation.
If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) $u=e^{-x} \cos y-e^{-y} \cos x$

Differentiate with respect to x as follows:

$u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x$

Differentiate with respect to y as follows:

$u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x$

Supplement the values in the given Laplace equation.

$e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0$

The given function in this case is the solution to the given Laplace equation.

(2) $u=\sin x \cosh y+\cos x \sinh y$

Differentiate with respect to x as follows:

$u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y$

Differentiate with respect to y as follows:

$u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y$

Substitute the values to obtain:

$-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0$
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0

2 years ago