The moles of KClO₃ that were consumed is 0.343 moles
<u><em>calculation</em></u>
2KClO₃ → 2KCl +3O₂
step 1: find the moles KCl
moles = mass÷ molar mass
25.6 g÷74.55 g/mol =0.343 moles
Step 2 : use the mole ratio to determine the moles KClO₃
from equation above KClO₃ : KCl is 2:2 =1:1
therefore the moles KClO₃ = 0.343 moles
2.9 imperial gallons =
13183.661 cubic centimetres
Question:
Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5 x103) kg of air?
Answer:
11.48106 L