At a high school, 18% of the students play football and 6% of the students play football and baseball. What is the probability t
hat a student plays baseball given that he plays football?
1 answer:
Answer:
33.3%
Step-by-step explanation:
Defining:
A: a student plays football
B: a student plays baseball
Data:
P(A∩B): a student plays football and baseball = 0.06
P(A) = 0.18
The probability that a student plays baseball given that he plays football is calculated as follows:
P(B/A) = P(A∩B)/P(A) = 0.06/0.18 = 0.33
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