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joja [24]
4 years ago
5

Hope someone can help

Mathematics
2 answers:
____ [38]4 years ago
5 0

First, convert 18,900 cm² into m²  

18,900 cm x \frac{1 m}{100 cm} x \frac{1 m}{100 cm} = 1.89 m²

  A = L x w

1.89 = L x 1.8

1.05 = L

Answer: 1.05 m

<u>Perimeter</u>

P = 2L + 2w

  = 2(32.5) + 2(18.4)

  = 65 + 36.8

  = 101.8

Answer: 101.8 m

<u>Area</u>

Area of Seating section = Area of big rectangle - area of small rectangle

A = (32.5 x 18.4) - (28 x 15)

  = 598 - 420

  = 178

Answer: 178 m

masha68 [24]4 years ago
5 0

Length = 1.89m

Perimeter of total area = 101.8m

Total area = 598m2

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Which of the following numbers is a factor of 49 ?
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5 X 4,257 estimate <br><br> Estimate <br><br> Answer <br><br><br> Please type it like that
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Answer: 20,000

Step-by-step explanation:

We can estimate the product of 5 and 4,257 by multiplying 5 by 4,000

5 * 4,000 = 20,000

The product of 5 and 4,257 is about 20,000

The real answer (not an estimate)

21,285

That is around 20,000 so we are correct

5 0
3 years ago
10. Determine whether or not, vectors ui(1,-2, 0, 3), u2 = (2, 3,0,-1), u3 = (3,9,-4,-2) e R is a linear combination of the (2,-
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If (2, -1, 2, 1) is a linear combination of the three given vectors, then there should exist c_1,c_2,c_3 such that

(2,-1,2,1)=c_1(1,-2,0,3)+c_2(2,3,0,-1)+c_3(3,9,-4,-2)

or equivalently, there should exist a solution to the system

\begin{cases}c_1+2c_2+3c_3=2\\-2c_1+3c_2+9c_3=-1\\-4c_3=2\\3c_1-c_2-2c_3=1\end{cases}

Right away we get c_3=-\dfrac12, so the system reduces to

\begin{cases}c_1+2c_2=\dfrac72\\\\-2c_1+3c_2=\dfrac72\\\\3c_1-c_2=0\end{cases}

Notice that the first equation is the sum of the latter two. The third equation gives us

3c_1-c_2=0\implies 3c_1=c_2

so that in the second equation,

-2c_1+3c_2=\dfrac72\implies7c_1=\dfrac72\implies c_1=\dfrac12

which in turn gives

3c_1=c_2\implies c_2=\dfrac32

and hence the (2, -1, 2, 1) is a linear combination of the given vectors, with

\boxed{(2,-1,2,1)=\dfrac12(1,-2,0,3)+\dfrac32(2,3,0,-1)-\dfrac12(3,9,-4,-2)}

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4 years ago
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