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vichka [17]
2 years ago
8

If y = 6, what is the value of x given 8x + 5y = 62? Answer:

Mathematics
2 answers:
ANTONII [103]2 years ago
5 0

the answer: y = 6 ⇔ x = 4

ok done. Thank to me :>

Tems11 [23]2 years ago
4 0

Answer:

2<u>s</u><u>q</u><u>e</u><u>a</u><u>r</u><u>h</u><u>a</u><u>h</u><u>a</u><u>h</u><u> </u><u>j</u><u>o</u><u>k</u><u>e</u><u> </u><u>b</u><u>y</u><u>e</u><u> </u><u>h</u><u>a</u><u>h</u><u>a</u><u>h</u>

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Positive Numbers are to the right of the number line.

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Through (2,-4), parallel to x=4
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3w + 7=8 need help with this
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Hope this helps you out 3w+7=8

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3w+7=8
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What is the least common multiple of 24 27 and108
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3 years ago
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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera
Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}

SP \approx 8.246

PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}

PA \approx  8.246

AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}

AZ \approx 8.246

ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}

ZS \approx 8.246

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

m_{SA} = \frac{6-(-4)}{6-(-4)}

m_{SA} = 1

m_{PZ} = \frac{4-(-2)}{-2-4}

m_{PZ} = -1

Since m_{SA}\cdot m_{PZ} = -1, diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)

M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)

M_{SA} = (-2,-2)+(3,3)

M_{SA} = (1,1)

M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)

M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)

M_{PZ} = (2,-1)+(-1,2)

M_{PZ} = (1,1)

Then, the diagonals SA and PZ bisect each other.

8 0
2 years ago
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