Question

Calculate the magnitude of the gravitational field of the moon at the location of Earth, in meters per square second.

Answer 1

Answer:

Step-by-step explanation:

We need to find magnitude of acceleration due to gravity on earth surface due to moon

$g_{m}=\frac{GM}{R^2}$

where M=mass of moon

R=distance between moon and earth

G=gravitational constant

$G=6.673\times 10^{-11}\ N-m^2/kg^2$

$M=7.35\times 10^{22}\ kg$

$R=3.84\times 10^8\ m$

$a_m=\frac{6.673\times 10^{-11}\times 7.35\times 10^{22}}{(3.84\times 10^8)^2}$

$a_m=3.33\times 10^{-5}\ m/s^2$