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gladu [14]
2 years ago
13

I need 3 more brainiest can anyone help a girl out plz

Mathematics
2 answers:
amid [387]2 years ago
7 0

Answer:

Sure

Step-by-step explanation:

Wewaii [24]2 years ago
6 0

Answer:

:/

Step-by-step explanation:

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Write an equation for the line, in point-slope form, that passes through the following point and has the following slope:slope:-
enyata [817]

Answer:

y+2=-4(x-1)

Step-by-step explanation:

y-y1=slope(x-x1)

just plug in the numbers you were given and youre good to go

5 0
3 years ago
A tree in Kira's backyard is 1/4 meters tall. It has been growing for 2 4/5 years.
Usimov [2.4K]

Answer:

0.0893 meters per year

Step-by-step explanation:

  1. 1/4 is 0.25
  2. 2 4/5 is 2.8
  3. divide height by year to get height gain per year
  4. 0.25/2.8 = 0. 0893 (to 3 SF)
4 0
2 years ago
List S and list T each contain 5 positive integers, and for each list the average (arithmetic mean) of the integers in the list
gtnhenbr [62]

Answer:

Yes, SDS > SDT

Step-by-step explanation:

List S

25, 30, 40, 50, XS

Average list S = 40

So, we could write,

Average list S = 40 = (25 + 30 + 40 + 50 + XS) / 5

Solving for XS

XS = 40 x 5 – 25 – 30 – 40 – 50 = 200 – 145 = 55  

SDs = SD (25, 30, 40, 50, 55) = 12.74

List T

30, 40, 45, 50, XT

Average list T = 40

So, we could write,

Average list T = 40 = (30 + 40 + 45 + 50 + XT) / 5

Solving for XT

XT = 40 x 5 – 30 – 40 – 45 – 50 = 200 – 165 = 35  

SDT = SD (30, 35, 40, 45, 50) = 7.1

Even at first sight SDS > SDT  because 25 is out of the range 30-50, while 45 is within that range.

List S is more spread than list T.

3 0
3 years ago
Ifa line segment has a length of 12 units and after a dilation the image
BlackZzzverrR [31]
<h3>Answer: Choice A) 1/3</h3>

================================================

Work Shown:

x = preimage length = 12

y = image length = 4

z = scale factor

z = y/x

z = 4/12

z = (1*4)/(3*4)

z = 1/3

The scale factor is 1/3.

This means the image is 1/3 of the length of the preimage.

4 0
3 years ago
Find the LCM of 2 and 3
max2010maxim [7]

\boxed{\sf  \: \begin{cases}\\\begin{gathered} {{{ \sf {\red{\large\bf { {\rm {\orange{\begin{array}{r | l}2&\underline{2,3}\\3&  \underline{1,3}\\&\underline{1,1}\ \: \end{array}}}}} }}}}}\end{gathered}\\\end{cases}}

LCM = 2 × 3 = 6

<u>LCM </u><u>of </u><u>2</u><u> </u><u>and</u><u> </u><u>3</u><u> </u><u>is </u><u>6</u>

8 0
3 years ago
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