Please help me thank you
1 answer:
Answer:
- f(4) = -12
- f(-2) = -6
- f(2) = -10
- f(0) = -8
- f(-3) = -5
Step-by-step explanation:
Put the value where the variable is and do the arithmetic.
Personally, I find it easier not to deal with so many minus signs. I would rewrite the function to ...
f(x) = -(8 +x)
I find it easier to evaluate the series of argument values when they are in increasing order. This serves as a check, because we expect the function values to be in decreasing order.
f({-3, -2, 0, 2, 4}) = -(8 +{-3, -2, 0, 2, 4}) = -{5, 6, 8, 10, 12} = {-5, -6, -8, -10, -12}
- f(4) = -12
- f(-2) = -6
- f(2) = -10
- f(0) = -8
- f(-3) = -5
_____
As always, for repetitive evaluation of the same function, a spreadsheet or graphing calculator is a handy tool.
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so, y=
Answer:
a) 0.0853
b) 0.0000
Step-by-step explanation:
Parameters given stated that;
H₀ : <em>p = </em>0.6
H₁ : <em>p = </em>0.6, this explains the acceptance region as;
p° ≤ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)
a).
the probability of type I error if exactly 60% is calculated as :
∝ = P (Reject H₀ | H₀ is true)
= P (p°>0.63 | p=0.6)
where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below
= P
= P
= P
= P [Z > 1.37]
= 1 - P [Z ≤ 1.37]
= 1 - Ф (1.37)
= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)
≅ 0.0853
b)
The probability of Type II error β is stated as:
β = P (Accept H₀ | H₁ is true)
= P [p° ≤ 0.63 | p = 0.75]
where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below
= P
= P
= P
= P [Z ≤ -6.20]
= Ф (-6.20)
≅ 0.0000 (from Cumulative Standard Normal Distribution Table).