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zepelin [54]
4 years ago
10

Evan is just leaving his house to visit his grandmother. Normally, the trip takes him 35 minutes on the freeway, going 70 mph. B

ut tonight he's running 5 minutes late. How fast will he need to drive on the freeway to make up the 5 minutes?
Physics
1 answer:
sdas [7]4 years ago
7 0

Answer:

Evan drive at speed = 81.67 m/hr

Explanation:

Normal speed of Evan = 70 m/hr

Time taken by Evan to visit his grandmother = 35 min = \frac{35}{60} hr

Distance covered by Evan = {speed}\times{time taken} = 70\times\frac{35}{60}

                                            = \frac{245}{6} miles

According to the problem, one day Evan was running 5 minutes late. So, the time Evan has to visit his grandmother is 30 mins.

To reach on time, Evan should be drive at the speed :

Speed = \frac{Distance}{Time}

           = \frac{\frac{245}{6} }{\frac{30}{60} }

          = 81.67 m/hr

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3 years ago
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1. There is a famous intersection in Kuala Lumpur, Malaysia, where thousands of vehicles pass each hour. A 750 kg Tesla Model S
tigry1 [53]

Solution :

Let the positive x-axis is along the East and the positive y direction is along the north.

Given :

Mass of the Tesla car, m_1 = 750 \ kg

Mass of the Ford car, m_2 = 1250 \ kg

Now let the initial velocity of Tesla car in the south direction be = -v_1j

The initial momentum of Tesla car, p_1 = -750 \ v_1

Let the initial velocity of Ford car in the east direction be = v_2 \ i

So the initial momentum of the Ford car is p_2=1250\ v_2 \ i

Therefore, the initial velocity of both the cars is p_i = p_1+p_2

                                                                  =1250 \ v_2 \ i - 750\ v_1 \ j

Now the final velocity of both the cars is v = 18 \ m/s

So the vector form is :

v = 18\cos 32\ i-18 \sin 32 \ j

  = 15.26 \ i - 9.54 \ j

Therefore the momentum after the accident is

p_f=(m_1+m_2) \times v

    =(750+1250) \times (15.26 \ i - 9.54 \ j)

    = 30520\ i -19080\ j

According to the law of conservation of momentum, we know

p_i = p_f

1250 \ v_2 \ i - 750\ v_1 \ j  = 30520\ i -19080\ j

1250 \ v_2 = 30520

v_2=24.4 \ m/s

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We get, v_1=25.4 \ m/s

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The speed of ford car before collision = 24.4 m/s

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Explanation:

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Explanation:

See attached file

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