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zepelin [54]
3 years ago
7

A person standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is t

he distance to the horizon from this point?

Physics
2 answers:
Fed [463]3 years ago
6 0

Explanation :

It is given that,

The radius of the earth is, r = 3959 mi

From the attached figure, we have to find the distance to the horizon from this point.

So, using Pythagoras theorem:

AP^2=OA^2-OP^2

x^2=(R+h)^2-R^2

x^2=(3959+4.3)^2-(3959)^2

x^2=34065.89\ mi

x=184.57\ mi

The distance to the horizon from this point is 184.57 mi.

Hence, this is the required solution.

PilotLPTM [1.2K]3 years ago
5 0
Besides ambitious, it would be 184.6 mi
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5. Graph A below plots a race car's speed for 5 seconds. The car's rate of acceleration is 6 m/s^2
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Answer:

The answer is below

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We are to check if the statement is true of false. If it is false, we correct the statement.

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5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

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8 0
2 years ago
a particle moves along the x axis with an acceleration of a=18t, where a has units if m/s2. if the particle at time t=0 is at th
ludmilkaskok [199]

Answer:

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           Velocity, v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c

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So velocity, v = (9t^2-12)m/s

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        Displacement, x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c

  We know that at t = 0, particle is at origin, x =0.

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Answer:

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