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zepelin [54]
3 years ago
7

A person standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is t

he distance to the horizon from this point?

Physics
2 answers:
Fed [463]3 years ago
6 0

Explanation :

It is given that,

The radius of the earth is, r = 3959 mi

From the attached figure, we have to find the distance to the horizon from this point.

So, using Pythagoras theorem:

AP^2=OA^2-OP^2

x^2=(R+h)^2-R^2

x^2=(3959+4.3)^2-(3959)^2

x^2=34065.89\ mi

x=184.57\ mi

The distance to the horizon from this point is 184.57 mi.

Hence, this is the required solution.

PilotLPTM [1.2K]3 years ago
5 0
Besides ambitious, it would be 184.6 mi
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Answer:

Correct answer:  Fg = m · g

Explanation:

Newton's second law states that if a resultant force is applied to an object, the object begins to move at an accelerated rate.

The formula that presents this is:

F = m · a  

this formula applies to an object moving on some surface

where m is the mass of the object and a the acceleration of the object

Let's take it now and watch the free fall:

The formula that presents this is:

Fg = m · g  

this formula applies to an object moving at free fall in vertical direction

Free fall is also an accelerated movement to which Newton's second law applies.

where m is the mass of the object and g the gravitation acceleration of the object . We also know that g is equal:

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3 years ago
Why are peer reviews important?
Pavlova-9 [17]

Answer:

Peer reviews are important because individuals with similar background knowledge are used to review work to detect inaccuracies or deficiencies in the work.

Explanation:

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7 0
3 years ago
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Iron has a known density of 7.9g/ml. If a sample of Iron has a mass of 84.5 grams, how many millimeters of water will the sample
dexar [7]

Answer:

10.6962 ml

Explanation:

the density of water is 1g/ml

if you devide the mass by density you get the volume the volume times density is equal to the mass so

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if you do that times 1g/ml is equal to 10.6962 g/ml.

5 0
3 years ago
What is the kinetic energy of a 1500 kg object moving at a velocity of 10 m/s?
Anastasy [175]
The Kinetic Energy Formula is as follows: KE = mass x velocity^2 /2

Plug in the correct numbers into the variables!

KE = 1500 kg x 10 m/s ^2 / 2

Square the 10 m/s!

KE = 1500 kg x 100 m/s / 2

Multiply!

KE = 150,000 / 2

Divide!

KE = 75,000 Newton-meters or Joules!


4 0
3 years ago
a constant current flows in the conductor with a magnitude of 1.6 mA. Calculate the charge and number of electrons transferred t
mrs_skeptik [129]
  • Current=1.6mA=1.6×10^{-3}A=0.0016A=I
  • Time=1h=3600s=t
  • Charge=Q

\\ \sf\longmapsto I=\dfrac{Q}{t}

\\ \sf\longmapsto Q=It

\\ \sf\longmapsto Q=0.0016(3600)

\\ \sf\longmapsto Q=5.76C

8 0
2 years ago
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