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eduard
3 years ago
13

Select the correct answers from the list.(1 point) A black hole begins to form as an aging star abruptly collapses when it cease

s__________ . This occurs after the star has consumed its component elements in this order___________.
Physics
2 answers:
Sidana [21]3 years ago
7 0

Answer:the comment is right

Explanation:

Anika [276]3 years ago
5 0

A black hole forms as a star collapses when it ceases emitting radiation from fusion reactions. This occurs after the star has consumed hydrogen, helium, then through iron.

Star evolution refers to the process by which stars evolve (change) over time.

A black hole can be defined as a collapsed star where the gravitational field in its nucleus becomes greater than particles cannot escape from it.

In consequence, black holes are cosmic bodies in which gravity is so powerful that nothing (i.e., particles, radiation, light, etc.) can escape from them.

Nuclear fusion refers to the energy reactions produced by the fusion of hydrogen at the core of a star, thereby becoming helium.

Learn more about black holes here:

brainly.com/question/10597324

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11. An example of a compound is<br> A. salt<br> B. salt water<br> C. sodium<br> D. soft drinks
katovenus [111]

Answer:

The correct answer is: A. salt

Explanation:

The salt corresponds to sodium chloride, whose chemical formula is NaCl. A compound is defined as that substance formed by a combination of 2 or more atoms.

8 0
3 years ago
The principal limitation of wind power is unpredictability.True or False
geniusboy [140]
True because you cannot see the wind
8 0
3 years ago
Read 2 more answers
a solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.48
ololo11 [35]

A solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.482.48n. 983 is the density of the object.

The substance's density is defined as its mass per unit of volume (volumetric mass density or specific mass). Although the Latin letter D may also be used, the symbol for density that is most usually used is (the lower case Greek letter rho). where V is the volume, is the density, and m is the mass. Weight per unit volume is a common informal definition of density, however this is incorrect scientifically; the actual term is specific weight. The US oil and gas industry serves as one illustration of this. A pure substance's mass concentration in numbers is equal to its density. To make density comparisons between different systems of units easier, it is occasionally replaced by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, usually water. If a substance's relative density to water is less than one, it will float in it. Temperature and pressure have an impact on a substance's density. This variation is frequently not very noticeable for solids and liquids, but it is very noticeable for gases. As pressure is applied, an object's density rises, which reduces the object's volume. With a few rare exceptions, as temperature increases, a substance's density decreases as its volume grows.

To know more about density please refer: brainly.com/question/15164682

#SPJ4

3 0
1 year ago
A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the
marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> v=\sqrt{\frac{kx^2}{m} }

v=\sqrt{\frac{400\times 0.220^2}{2} }

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0
3 years ago
What length of a certain metal wire of diameter 0.15 mm is needed for the wire to have a resistance of 15 ω? the resistivity of
Murljashka [212]

The resistance of the cylindrical wire is R=\frac{\rho l}{A}.

Here R is the resistance, l is the length of the wire and A is the area of cross section. Since the wire is cylindrical A=\frac{\pi d^2}{4} . Rearranging the above equation,

A=\frac{\rho l}{R}\\  \frac{\pi d^2}{4}=\frac{\rho l}{R}\\  l=\frac{\pi d^2 R}{4 \rho}

Here d=0.15, R=15, \rho=1.68(10^{-8}).

Substituting numerical values,

l=\frac{\pi 0.15^2(10^{-6}) (15)}{4 (1.68)(10^{-8})}  \\ l=15.78

The length of the wire is 15.78 \;\;m

5 0
4 years ago
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