There are two laws named for Kirchhoff. The both concern electrical circuits.
Here they are in my own words:
1). The sum of the voltage drops around any closed loop in a circuit is zero.
2). The sum of the currents at any single point in a circuit is zero.
K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J
The Hubble Space Telescope is a joint ESA/NASA project and was launched in 1990 by the Space Shuttle mission STS-31 into a low-Earth orbit 569 km above the ground. During its lifetime Hubble has become one of the most important science projects ever. Hope this helps! ~ Autumn :)
Answer:
a) v = 19,149.6 m/s
b) f = 95%
c) t = 346.5min
Explanation:
First put all values in metric units:

The equation of motion you need is:
where
is the final velocity, a is acceleration and t is time in hours.
Since the spaceship starts from 0 velocity:

Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:

solving for first and last interval:
Since the spaceship starts and finish with 0 velocity:

Then the ship traveled
at constant speed, which means that it traveled:

Which in percentage is 95% of the trip.
to calculate total time you need to calculate the time used during constant speed:

That added to the other interval times:
