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Cloud [144]
3 years ago
11

Convert minutes to hours 13. 10 minutes 14 40 minutes 12. 15 minutes I

Mathematics
2 answers:
Pie3 years ago
8 0
13. 0.167
14. 0.667
15. 0.25
geniusboy [140]3 years ago
3 0

Answer:

13. 1/6 of an hour, or 0.166

14. 2/3 of an hour, or 0.666

12. 1/4 of an hour, or 0.25

Step-by-step explanation:

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What is the question?
6 0
3 years ago
QUÉ ES EL BASTA NUMÉRICO
Lemur [1.5K]

Answer:

relating to or expressed as a number or numbers.

Step-by-step explanation:

8 0
2 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
A university is interested in promoting graduates of its honors program by establishing that the mean GPA of these graduates exc
den301095 [7]

Step-by-step explanation:

Population Mean (u) = 3.50

Sample (n)= 36

Sample mean (x) = 3.60

Population standard deviation (s)= 0.40

Test statistics:

(Null hypothesis) H0: u= 3.5 (Population mean is equal to 3.5)

(Alternate hypothesis) H1: u> 3.5 (Population mean is greater than 3.5)

Z= \frac{x-u}{\frac{s}{\sqrt{n} } }= \frac{3.60-3.50}{\frac{0.4}{\sqrt{36} } }= \frac{0.10}{0.067}= 1.5

critical value= Z0.05= 1.645 (From Z table)

Since, Z value is less than critical Z value that is Z<1.645

We cannot reject null hypothesis

So, we decide to reject that the mean GPA of graduates exceeds 3.50

3 0
2 years ago
Eli needs to save $235. to earn money, he plans to mow lawns and charge $21 for each, write two estimates eli could use to deter
Illusion [34]
<span>To determine the number of lawns he needs to mow to earn the desired money, Eli could perform a simple addition problem, adding $21 per lawn until he reached his goal number. This equation would be: 21 + 21 = 42 + 21 = 63 + 21 = 84 + 21 = 105 + 21 = 126 + 21 = 147 + 21 = 168 + 21 = 189 + 21 = 210 + 21 = 231 + 21 = 252. However, a better way would be to divide the desired amount by the cost per lawn and round to the nearest whole number. That equation is 235 / 21 = 12 lawns.</span>
3 0
3 years ago
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