Answer:
relating to or expressed as a number or numbers.
Step-by-step explanation:
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
Step-by-step explanation:
Population Mean (u) = 3.50
Sample (n)= 36
Sample mean (x) = 3.60
Population standard deviation (s)= 0.40
Test statistics:
(Null hypothesis) H0: u= 3.5 (Population mean is equal to 3.5)
(Alternate hypothesis) H1: u> 3.5 (Population mean is greater than 3.5)
Z=
=
=
= 1.5
critical value= Z0.05= 1.645 (From Z table)
Since, Z value is less than critical Z value that is Z<1.645
We cannot reject null hypothesis
So, we decide to reject that the mean GPA of graduates exceeds 3.50
<span>To determine the number of lawns he needs to mow to earn the desired money, Eli could perform a simple addition problem, adding $21 per lawn until he reached his goal number. This equation would be: 21 + 21 = 42 + 21 = 63 + 21 = 84 + 21 = 105 + 21 = 126 + 21 = 147 + 21 = 168 + 21 = 189 + 21 = 210 + 21 = 231 + 21 = 252. However, a better way would be to divide the desired amount by the cost per lawn and round to the nearest whole number. That equation is 235 / 21 = 12 lawns.</span>