A 1.5 x 10^3 kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its
1 answer:
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Answer:
270 mi/h
Explanation:
Given that,
To the south,
v₁ = 300 mi/h, t₁ = 2 h
We can find distance, d₁
To the north,
v₂ = 250 mi/h, d₂ = 750 miles
We can find time, t₂
Now,
Average speed = total distance/total time
Hence, the average speed for the trip is 270 mi/h.