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pogonyaev
3 years ago
7

A 1.5 x 10^3 kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its

velocity to 2.0 meters per second east.
Determine the magnitude and direction if the braking force.​
Physics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

2400 N west

Explanation:

J=ft

-1200/5 = 5t/5

-2400n=t -> 2400 N west

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