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andrew-mc [135]
3 years ago
9

Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.360 mmmm wide. The diffraction pattern is obse

rved on a screen 2.90 mm away. Define the width of a bright fringe as the distance between the minima on either side.
Physics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

      Δy= 5,075 10⁻⁶ m

Explanation:

The expression that describes the interference phenomenon is

      d sin θ = (m + ½) λ

As the observation is on a distant screen

     tan θ = y / x

     tan θ= sin θ/cos θ

As in ethanes I will experience the separation of the vines is small and the distance to the big screen

          tan θ = sin θ

Let's replace

     d y / x = (m + ½) λ

The width of a bright stripe at the difference in distance  

     y₁ = (m + ½) λ x / d

     m = 1

      y₁ = 3/2 λ x / d

Let's use m = 1, we look for the following interference,

             m = 2

             y₂ = (2+ ½) λ x / d

The distance to the screen is constant x₁ = x₂ = x₀

The width of the bright stripe is

           Δy = λ x / d (5/2 -3/2)

           Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)

           Δy= 5,075 10⁻⁶ m

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A 5.0 g coin is placed 15 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the t
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Answer:

the coin does not slide off

Explanation:

mass (m) = 5 g = 0.005 kg

distance (r) = 15 cm = 0.15 m

static coefficient of friction (μs) = 0.8

kinetic coefficient of friction (μk) = 0.5

speed (f) = 60 rpm

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lets first find the angular speed of the table

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ω = 2 x π x 60 x \frac{1}{60}

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Now lets find the maximum static force between the coin and the table so we can get the maximum velocity the coin can handle without sliding

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Vmax = 1.08 m/s

ωmax = \frac{Vmax}{r}

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now that we have the maximum angular acceleration of the table, we can calculate its maximum speed in rpm

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since the table is rotating at a speed less than the maximum speed that the static friction can hold coin on the table with, the coin would not slide off.

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