The object's speed will remain constant after the it leaves his hand.
So will HIS speed in the opposite direction.
Answer:
L = 5,955 m
Explanation:
For this exercise we must use the relation
R = ρ L / A
where R is the resistance that indicates that it is 1 Ω, the resistivity is taken from the tables ρ = 2.82 10⁻⁸ Ω m, L is the length of the wire and A is the cross section.
As it indicates to us in volume of aluminum to use we divide the two terms by the length
R / L = ρ L / (A L)
the volume of a body is its area times its length, therefore
R / L = ρ L / V
R = ρ L² / V
we clear the length of the wire
L = √ R V /ρ
we reduce the volume to SI units
v = 1 cm³ (1m / 10² cm)³ = 1 10⁻⁶ m
let's calculate
L = √ (1 1 10⁻⁶ / 2.82 10⁻⁸)
L = √ (0.3546 10²)
L = 5,955 m
Answer:
24mph
Explanation:
it really depends how high but the average speed for that quick will be atleast 24mph if not try 42mph if it is wrong
Answer:
v (speed) = S / t = 4 * 400 m / (6 * 60 sec) = 4.4 m/s
The average velocity is zero because there is no net vector displacement.
