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3 years ago

Solve the system using elimination.

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer:

B. (-3,-8)

Step-by-step explanation:

I have aced tests on these. You can trust this is correct - plus it's verified by a calculator.

Gelneren [198K]3 years ago

4 0

Answer:

Step-by-step explanation:

x - 4y = 4 → (1)

3x - 4y = - 12 → (2)

Multiplying (1) by - 1 and adding to (2) will eliminate the y- term

- x + 4y = - 4 → (3)

Add (2) and (3) term by term to eliminate y

2x + 0 = - 16

2x = - 16 ( divide both sides by 2 )

x = - 8

Substitute x = - 8 into either of the 2 equations and solve for y

Substituting into (1)

- 8 - 4y = 4 ( add 8 to both sides )

- 4y = 12 ( divide both sides by - 4 )

y = - 3

solution is (- 8, - 3 ) → B

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Can I get help on 37 please someone

GaryK [48]

Answer:

Step-by-step explanation:

B is the correct answer.

8 0

4 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

Whats A O E in the diagram for A O C

Orlov [11]

Answer:

where is the picture or graph

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Step-by-step explanation:

8 0

3 years ago

SOMEONE HELP BECAUSE I DONT GET THIS

Leno4ka [110]

Answer:

x = 18

m<A = 166°

Step-by-step explanation:

The parallel lines are cut by a transversal, so corresponding angles A and B are congruent.

7x + 40 = 3x + 112

4x = 72

x = 18

m<A = 7x + 40 = 7(18) + 40 = 126 + 40 = 166

6 0

3 years ago

Read 2 more answers

Which is a statistical question?

attashe74 [19]

I’m pretty sure the answer is D. Sorry if I’m wrong

8 0

3 years ago