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ivolga24 [154]
3 years ago
8

What is the factored form of a2 – 121?

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

The factored form a^2-121 is (a+11)(a-11).

Step-by-step explanation:

Given : a^2-121

We have to write the given expression in factored form.

Factor form of an expression is writing the expression in lower power form such that the product of factors given the original expression

Consider the given expression  a^2-121.

We know the algebraic identity x^2-y^2=(x+y)(x-y)

Here a^2-121=a^2-(11)^2.

Comparing with identity stated above , we have x= a , b = 11 , thus, we get

a^2-(11)^2=(a+11)(a-11).

Thus, the factored form a^2-121 is (a+11)(a-11).

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Martin wants to buy 4 plastic figures that cost $17 each. How much money does he need to save to purchase the figure?
Nat2105 [25]
1 figure = $17 so you multiply 4 and 17 to get 68 
Martin will need to save $68
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2 years ago
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What is the sum 10 + (-10)
Marta_Voda [28]

Answer:

0

Step-by-step explanation:

because

k  c  r

10 + (-10)

10 - 10=0

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2 years ago
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What was the total production of gasoline and kerosene combined (in Barrels)
Elina [12.6K]

The amount of kerosene and gasoline produced is an illustration of equations.

<em>44.4 million barrels of gasoline and kerosene are produced</em>

Let

<em />x \to<em> Proportion of kerosene</em>

<em />y \to<em>  Proportion of Gasoline</em>

<em />

So:

x = 40\%

y = 34\%

Total = 60\ million ---- total barrels produced

The amount of Kerosene produced is:

Kerosene =x \times Total

Kerosene =40\% \times 60\ million

Kerosene = 24\ million

The amount of Gasoline produced is:

Gasoline  =y \times Total

Gasoline  =34\% \times 60\ million

Gasoline  =20.4\ million

So, the total production of both is:

Total = Kerosene + Gasolene

Total = 24\ million + 20.4\ million

Total = 44.4 million

<em>Hence, 44.4 million barrels of gasoline and kerosene are produced</em>

Read more about equations at:

brainly.com/question/21105092

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2 years ago
Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of
tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

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Write 337,060 in expanded form using exponent
mario62 [17]


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Add as Brainliest answer when you get the chance to :)

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5 0
3 years ago
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