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Softa [21]
2 years ago
12

Solve (2x + 5)= (2x + 3)(2x - 1)

Mathematics
2 answers:
____ [38]2 years ago
6 0

Answer:

x = -1± sqrt( 33)

    ----------------------------

             4

Step-by-step explanation:

(2x + 5)= (2x + 3)(2x - 1)

Distribute

2x+5 = 4x^2 +6x-2x-3

Combine like terms

2x+5 = 4x^2 +4x -3

Subtract 2x +5 from each side

0 = 4x^2 +4x-3-2x-5

Combine like terms

0 =4x^2 +2x -8

Using the quadratic formula

a=4  b=2  c=-8

x = -b± sqrt( b^2-4ac)

    ----------------------------

             2a

x = -2± sqrt( 2^2-4(4)(-8))

    ----------------------------

             2(4)

x = -2± sqrt( 4+128)

    ----------------------------

             8

x = -2± sqrt( 132)

    ----------------------------

             8

x = -2± 2sqrt( 33)

    ----------------------------

             8

x = -1± sqrt( 33)

    ----------------------------

             4

AlexFokin [52]2 years ago
4 0

(2x + 5)= (2x + 3)(2x - 1)\\2x+5=4x^2-2x+6x-3\\4x^2-2x+6x-3-2x-5=0\\4x^2+2x-8=0\\(4x+1-\sqrt{33})( 4x+1+\sqrt{33})=0 \\ x=\frac{-1+\sqrt{33} }{4} /or/x=\frac{-1-\sqrt{33} }{4}

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Answer:

a. <u>Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. <u>The probability is 0.2029 or 20.29%</u>

c. <u>The probability is 0.2029 or 20.29%</u>

d. <u>The probability is 0.1671 or 16.71%</u>

e. <u>The probability is 0.9975 or 99.75%</u>

Step-by-step explanation:

<u>a. Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. Let's use the binomial distribution table, this way:

Binomial distribution (n=10, p=0.697)

 f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0000 0.0000

1 0.0002 0.0002

2 0.0016 0.0017

3 0.0095 0.0112

4 0.0384 0.0496

5 0.1059 0.1555

6 <u>0.2029</u> 0.3584

7 0.2668 0.6252

8 0.2301 0.8553

9 0.1176 0.9729

10 0.0271 1.0000

<u>The probability is 0.2029 or 20.29%</u>

c. If 69.7% of 18-20 years old consumed alcoholic beverages in 2008, therefore, 30.3% did not and the binomial distribution table is:

Binomial distribution (n=10, p=0.303)

 f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0271 0.0271

1 0.1176 0.1447

2 0.2301 0.3748

3 0.2668 0.6416

4 <u>0.2029</u> 0.8445

5 0.1059 0.9504

6 0.0384 0.9888

7 0.0095 0.9983

8 0.0016 0.9998

9 0.0002 1.0000

10 0.0000 1.0000

<u>The probability is 0.2029 or 20.29%</u>

d. Let's use the binomial distribution table, this way:

Binomial distribution (n=5, p=0.697)

 f(x) F(x) 1 - F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0026 0.0026

1 0.0294 0.0319

2 0.1351 <u>0.1671 </u>

3 0.3109 0.4779

4 0.3576 0.8355

5 0.1645 1.0000

P(0) + P(1) + P (2) = 0.0026 + 0.0294 + 0.1351

<u>The probability is 0.1671 or 16.71%</u>

e. Using the same binomial distribution table we used in d. we have:

P(1) + P (2) + P(3) + P(4) + P (5) = 0.0294 + 0.1351 + 0.3109 + 0.3576 + 0.1645

<u>The probability is 0.9975 or 99.75%</u>

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but if only positive, x can be = 1,2

" " negative, x can be = -1, -2

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210/7

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