Answer:
The distance can the water be projected is 4.51 m
Explanation:
The speed of the water in the hose is equal to:
v1 = R/A1
If we solve the continuity for v2:
v2 = R/A2 (eq. 1)
The equation for the vertical position is:
yf = yi + vy*t - (1/2)gt²
yi = 0
vy = 0
Clearing t:
(eq. 2)
The equation for position is:
xf = xi + vxt = 0 + v2t = v2t (eq. 3)
Replacing equation 1 and 2 in equation 3:
Answer:
181 m
Explanation:
a = v² / r
6.09 (9.81 m/s²) = (104 m/s)² / r
r = 181 m
Answer:
1. Largest force: C; smallest force: B; 2. ratio = 9:1
Explanation:
The formula for the force exerted between two charges is
where K is the Coulomb constant.
q₁ and q₂ are also identical and constant, so Kq₁q₂ is also constant.
For simplicity, let's combine Kq₁q₂ into a single constant, k.
Then, we can write
1. Net force on each particle
Let's
- Call the distance between adjacent charges d.
- Remember that like charges repel and unlike charges attract.
Define forces exerted to the right as positive and those to the left as negative.
(a) Force on A
(b) Force on B
(C) Force on C
(d) Force on D
(e) Relative net forces
In comparing net forces, we are interested in their magnitude, not their direction (sign), so we use their absolute values.
2. Ratio of largest force to smallest
Distance is 50 km
Displacement is 10 km
<u>Explanation:</u>
Given:
Distance toward south, x = 25 km
Distance towards west, y = 10 km
Distance towards north, z = 15 km
(a) Total distance, D = ?
Total distance, D = x + y + z
D = 25 + 10 + 15
D = 50km
(b) Displacement, d = ?
Displacement = final position - initial position
= 10 - 0 km
= 10km