Period, T = 1/ f.
f = frequency = 200 Hz.
Period T = 1/200 = 0.005 seconds.
E=kq/r^2
q=(E*r^2)/k
q=(.086N/C)(1.7m^2)/(8.99*10^9N*m^2/C^2)
q=2.76*10^-11 C
q=2.8*10^-11 C
Speaking that the trash can absorb the momentum. It only should go 5
Answer:
3.117 m
Explanation:
Given that:
the distance of separation between speaker A and speaker B (L) = 6.69 m
Frequency (F) = 750 -Hz tone
Velocity of speed of sound = 343 m/s
The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

where A = 
we have:






∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m
It will have it’s greatest velocity right before the projectile hits the ground. At the instant it makes contact it become zero and the displacement changes to an upward direction rather than down