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4 years ago

Jupiter is 5.2 times farther from the sun than Earth is. Find Jupiter’s orbital period in Earth years

1 answer:

8 0

You can solve this using Kepler's 3rd law. T is proportional to r^1.5. T(J) = T(E)*5.2^1.5 = 11.86 years.
<span>You can also solve it the hard way: Find M (sun's mass) and r(Jupiter's orbital radius) in m. Then use Kepler's equation T = 2pi*r^1.5/sqrt(GM).</span>

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A teacher asks students to identify which demonstrations show physical changes and which show chemical changes.

givi [52]

Answer:

B. A dish of water is placed in the freezer and turns solid

Explanation:

it is a physical change because it can return to its original state by physical means. the other options are chemical changes because things like color change, bubbles or fizzing, and odor change all indicate a chemical change and cannot return to the original state it was in before.

3 0

3 years ago

A massless rope passes over a massless pulley suspended from the ceiling. A 4-kg block is attached to one end and a 5-kg block i

borishaifa [10]

The acceleration on the 5kg block is 1.088m/s^2

Data;

mass(a) = 4kg
mass (b) = 5kg
acceleration of the 5kg block.

<h3>The Acceleration on the 5kg block</h3>

To solve this question, we just need to use Newton's second law of motion which states that "the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."

$F_n_e_t = M_t_o_t_a_l * a\\F = ma\\F_n_e_t = mg\\$

But then the force on both sides will be

$mg = ma\\5g - 4g= (4+5) a\\(5-4)g = 9a\\g = 9a\\a = \frac{g}{9} \\a = \frac{9.80}{9} \\a = 1.088 m/s^2$

The acceleration on the 5kg block is 1.088m/s^2

Learn more on newton's second law of motion here;

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brainly.com/question/13447525

4 0

2 years ago

Susan was traveling in an airplane. She looked out of a window in the airplane and saw clouds in the sky. Why could Susan see cl

lutik1710 [3]

The correct answer Is C

8 0

3 years ago

A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i

Lubov Fominskaja [6]

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

3 0

3 years ago

Potential energy is the energy an object has because of its

Naya [18.7K]

Radiation compared to other potential

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2 years ago