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2 years ago

What experimental evidence led to the development of this atomic model from the one before it?

1 answer:

8 0

A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.

<h3>What is the Rutherford experiment?</h3>

Rutherford performed an experiment in which alpha particles are bombarded on the gold foil.

Some of the particles bounced back which indicates that there are heavy particles present in the center of an atom.

Most alpha particles pass through the atom which indicates that there is a lot of empty space in an atom.

A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.

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You might be interested in

Which energy conversion correctly describes what happens when you are dancing

geniusboy [140]

Kinetic because u are moving around a lot!

6 0

3 years ago

A cheetah runs with a positive acceleration. What does this tell you about the velocity time graph for the cheetah?

Katarina [22]

B is the correct answer

3 0

3 years ago

A -0.00325 C charge q1 is placed 5.62 m from a second charge q2. The first charge is repelled with a 48900 N force. What is the

blagie [28]

Answer: q2 = -0.05286

Explanation:

Given that

Charge q1 = - 0.00325C

Electric force F = 48900N

The electric field strength experienced by the charge will be force per unit charge. That is

E = F/q

Substitute F and q into the formula

E = 48900/0.00325

E = 15046153.85 N/C

The value of the repelled second charge will be achieved by using the formula

E = kq/d^2

Where the value of constant

k = 8.99×10^9Nm^2/C^2

d = 5.62m

Substitutes E, d and k into the formula

15046153.85 = 8.99×10^9q/5.62^2

15046153.85 = 284634186.5q

Make q the subject of formula

q2 = 15046153.85/ 28463416.5

q2 = 0.05286

Since they repelled each other, q2 will be negative. Therefore,

q2 = -0.05286

6 0

3 years ago

Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.

Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and $g=9.8m/s^2$ the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

$\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}$

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

$\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}$

$\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}$

$d=35.35\ m$

The range is 35.35 m

7 0

3 years ago

Dr. Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paint

skad [1K]

The option that could be the hypothesis for this experiment is that D. Abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

<h3>What is a hypothesis?</h3>

It should be noted that a hypothesis simply means the proposed explanation made on the basis of limited evidence.

From the information, Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paintings.

Therefore, the option that could be the hypothesis for this experiment is that abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

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3 0

2 years ago