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2 years ago

Emissions from alpha decay require the least amount of shielding.

1 answer:

6 0

The particles released during alpha decay are called alpha particles. Alpha particles have greater mass and charge than other emitted particles.

Radioactive emissions are the transfer of energy through the flow of particles or waves in a medium
There are 3 types of radioactive emissions which are alpha, beta and gamma
In alpha radiation, the nucleus emits an alpha particle which is equivalent to a helium nucleus
In beta radiation, an electron is emitted to convert a neutron to a proton
In gamma radiation, the nucleus just loses energy

Since alpha particles have more mass and charge, they are more ionising and lose more energy at a faster rate and can be blocked easily.

Learn more about alpha decay emissions here:

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Advantages and Disadvantages of a clinical thermometer

lidiya [134]

Answer:

Explanation:Advatages

1..Its takes precise reading accurate

2. it is moveable because of its small weight

3.It is easy to read and can be kept inside water

Disadvantages

1. It breaks easily because of its small size

2. If broken there can be risk of exposure to mercury chemicals.

4 0

4 years ago

7. En la sala de una casa hay una gran ventana de vidrio, por la que se presenta una pérdida significativa de calor; las medidas

jonny [76]

Answer:

I DON'T SPEAK TACO BELL!

Explanation:

7 0

3 years ago

When the mass of the cylinder increased from 3.0 kg to 6.0 kg, what happened to the amount of heat generated in the system?

seropon [69]

here's what you require:

The mass of the material,

The temperature change that occurs,

The specific heat capacity of the material,

This is the amount of heat required to raise 1 gram of that substance by 1°C.

The heat will increase

5 0

3 years ago

Read 2 more answers

what is the efficiency of a machine that can carry a load of 100 kg with an effort of 20N when its velicity ratio is 10 ASAP

Salsk061 [2.6K]

Answer:

Efficiency of machine=4.9

Explanation:

We are given that

Mass of load=100 kg

Effort=20 N

Velocity ratio=10

We have to find the efficiency of machine.

Load= $mg=100\times 9.8=980 N$

Efficiency= $\frac{Load}{effort}\times \frac{1}{velocity\;ratio}$

Using the formula

Efficiency of machine= $\frac{980}{20}\times \frac{1}{10}$

Efficiency of machine= $\frac{49}{10}$

Efficiency of machine=4.9

7 0

4 years ago

Two charged concentric spheres have radii of 0.008 m and 0.018 m. The charge on the inner sphere is 3.62 10-8 C and that on the

Alekssandra [29.7K]

Answer:

The electric field is $E = 2.2625 *10^{6} \ N/C$

Explanation:

From the question we are told that

The radius of the inner sphere is $r_1 = 0.008\ m$

The radius of the outer sphere is $r _2 = 0.018 \ m$

The charge on the inner sphere is $q_1 = 3.62 *10^{-8} \ C$

The charge on the outer sphere is $q_2 = 1.62 *10^{-8} \ C$

The position from the origin is $d = 0.012 \ m$

Generally the electric field is mathematically represented as

$E = \frac{k (q_1 )}{ r^2}$

The reason for using $q_1$ for the calculation is due to the fact that the position considered is greater than the $r_1$ but less than $r_2$

Here k is the Coulomb constant with value $k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A{-2}$

$E = \frac{9*10^9 (3.62 *10^{-8}}{0.012^2}$

$E = 2.2625 *10^{6} \ N/C$

6 0

3 years ago