1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana [24]
2 years ago
8

What is the difference between a conductor and an insulator?

Chemistry
1 answer:
Zielflug [23.3K]2 years ago
5 0
A conductor is what helps heat or electricity pass through an object. Examples of conductors are, silver, iron, aluminum, etc..

An insulator does the opposite and instead, stops either from going through. Examples of an insulator is paper, wood, rubber, etc.
You might be interested in
What is the mass of 6.78x1050 molecules of NaCl
ryzh [129]

Answer:

Explanation:

As

Molar mass of NaCl= 58.44 gm

So we got it that,

58.44 mass of NaCl contain = 6.023*10^23  molecules of Na Cl

x mass will contain = 6.78*10^50

by cross multiplication , we get

x=  58.44*(6.78*10^50)/  6.023*10^23  

x= 65.785 * 10^27  molecules

Plz Brain-list\support me by Subscribing my channel "ZK SOFT&GAMING"

6 0
3 years ago
Which graph should be used to describe the
Tasya [4]
A I think that a bar graph would best represent this information.
3 0
3 years ago
Read 2 more answers
Given the following reaction:
fredd [130]

Answer:D. In order to restore equilibrium, the reaction shifts right, towards products

Explanation:

7 0
2 years ago
What is the interval used on the y-axis of this graph?
bezimeni [28]

Answer:

5

Explanation:

the numbers go up by 5

7 0
3 years ago
If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

7 0
3 years ago
Other questions:
  • Which characteristic of life is demonstrated when eagles use sharp talons to grab fish from the water?
    7·2 answers
  • An atom that has lost or gained electrons is known as an ion. Which compound below is made up of ions?
    15·1 answer
  • The way metals surface reflects light is called
    7·2 answers
  • Write a balanced chemical equation for the reaction. feso4 and pb(no3)2 express your answer as a chemical equation. identify all
    10·2 answers
  • Daniel has a sample of pure copper. Its mass is 89.6 grams (g), and its volume is 10 cubic centimeters (cm3). What’s the density
    5·2 answers
  • The most active metals on the periodic table are found on the: lower left upper right middle upper left lower right
    5·2 answers
  • What is the scientific word : <br><br>molecules of an element containing three of the same type
    13·1 answer
  • Which of the following correctly identifies the number of each element involved in the chemical formulas
    8·1 answer
  • Nitrogen gas can be prepared by passing gaseous ammonia over solid copper (II) oxide at high temperatures. If 18.1 g of Nh3 is r
    11·1 answer
  • A student proposes creating a buffer by dissolving 0.010mol of NaClO4(s) in 100.mL of 0.100MHClO4. Explain why the resulting sol
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!