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CaHeK987 [17]
3 years ago
6

Find the ph of a 0.250 m solution of nac2h3o2. (the ka value of hc2h3o2 is 1.80×10−5). express your answer numerically to four s

ignificant figures.
Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0
Answer is: pH value of solution of NaC₂H₃O₂ is 9.07.
Chemical reaction: C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻.
Ka(HC₂H₃O₂) = 1,8·10⁻⁵.<span>
Ka · Kb = Kw.
</span>1,8·10⁻⁵ mol/dm³ · Kb = 1·10⁻¹⁴ mol²/dm⁶; the ionic product of water at 25°C.<span>
Kb(</span>C₂H₃O₂⁻) = 1·10⁻¹⁴ mol²/dm⁶ ÷ 1,8·10⁻⁵ mol/dm³.<span>
Kb(</span>C₂H₃O₂⁻) = 5,56·10⁻¹⁰ mol/dm³.
c(C₂H₃O₂⁻) = 0,25 M.
[OH⁻] = [HC₂H₃O₂] = x.
[C₂H₃O₂⁻] = 0,25 M - x.
Kb = [OH⁻] · [HC₂H₃O₂] / [C₂H₃O₂⁻].
5,56·10⁻¹⁰ = x² / (0,25 M -x).
Solve quadratic equation: x = [OH⁻] = 0,0000118 M.
pOH = -log[OH⁻] = -log(0,0000118M) = 4,93.
pH + pOH = 14.
pH = 14 - 4,93 = 9,07.
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Question 2
Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0
3 years ago
Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4
Aleksandr [31]

The concentration of hydroxide ion is  5  \times 10^ − 14  M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

                          H C l O 4  ⇌  H +  +  C l O  4 -

Moreover, let's assume that  H C l O 4  is a strong acid and will fully dissociate.

Hence,

                              [ H + ]  =  0.20  M

Now, recall,  

                  K w  =  [ H + ] [ O H − ]  =  1.0  \times 10 ^− 14

Hence,

                  ⇒ [ O H − ]  =  K w  / [ H + ]  = 5  \times 10^ − 14  M.

7 0
3 years ago
Using 273.15 K as the value for Zero degree Celsius convert 45.1° C to Kelvin. 6.05 K 318 K 318.3 K 1.23 x 104 K
OLEGan [10]
Zero degree celcius = 273.15 degree kelvin

Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).

Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin

Approximating to the nearest tenth, the value will be 318.3 degree kelvin
8 0
3 years ago
What is the mass number of 80Br
Amanda [17]
Mass number of an element write in bottom of it!

So, there 80 would be the mass number of ₈₀Br.

Hope this helps!
4 0
3 years ago
1. In which order does food travel through the digestive
lisov135 [29]

Answer:

B :)

Explanation:

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