In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called
cellular respiration
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume = 4 L
Initial temperature = 300 K
Final volume = 2 L
Final temperature = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 300 K × 2L / 4 L
T₂ = 600 L.K / 4 L
T₂ = 150 K
Answer:
(1) addition of HBr to 2-methyl-2-pentene
Explanation:
In this case, we will have the formation of a <u>carbocation</u> for each molecule. For molecule 1 we will have a <u>tertiary carbocation</u> and for molecule 2 we will have a <u>secondary carbocation</u>.
Therefore the <u>most stable carbocation</u> is the one produced by the 2-methyl-2-pentene. So, this molecule would react faster than 4-methyl-1-pentene. (See figure)
Answer:
Potassium (K) and Lithium (Li) for the fist one i cant see the second
Explanation:
Answer:
d
Explanation:
sugar molecules are being broken down
