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Vinvika [58]
2 years ago
15

Choose one metal from the reactivity series that will react safely with dilute sulphuric acid

Chemistry
1 answer:
IceJOKER [234]2 years ago
7 0

Answer:

Zinc (Zn) will safely react with dilute sulphuric acid.

Explanation:

If correct please give brainliest

<em>Stay safe and healthy</em>

Thank You

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Most elements on the periodic table are
ivanzaharov [21]

Answer:

Metals

Explanation:

hope this helps

5 0
2 years ago
Read 2 more answers
A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass. to answer the question, enter th
arlik [135]
Empirical   formula  is  calculated   as  follows

calculate  the  moles  of  each  element,  that  is   %  composition/  molar  mass
molar  masses  (  Si=  28.09g/mol ,  Cl=  35.5  g/mol,  I=126.9 g/mol)

moles  of  silicon =  7.962/28.09g/mol=  0.283  moles
moles  of  chlorine =  20.10 / 35.5g/mol =  0.566  moles
moles  of  iodine=  71.94 / 126.9  g/mol=  0.567  moles

divide  each  mole   with  smallest    mole  (0.283)
that  is    silicon =  0.283/0.283= 1 mole
             chlorine =  0.566/0.283=  2 mole
            Iodine=  o.567/0.283= 2  moles
empirical  formula  is  therefore=  SiCl2I2


5 0
2 years ago
Of the following choices, pick all that are uses for radiation. Check all that
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A B C these are the answers hopes this help <3
8 0
2 years ago
A 35 MGD surface Water treatement plant proposes to to use alum Coagulation for turbidity reduction using 44 mg/ L alum. the raw
CaHeK987 [17]
C) is the water alkainty adequate. I.e
5 0
2 years ago
By the reaction of carbon &amp; oxygen , a mixture of CO &amp;CO2 is obtained. What is the composition by mass of the mixture ob
Hatshy [7]
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

   2C     +     O₂      →    2CO
1 mol    0.625 mol        1 mol
         0.625-0.5=0.125 mol

      2CO    +         O₂       →        2CO₂
0.250 mol       0.125 mol       0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g

n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
4 0
3 years ago
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