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cestrela7 [59]
3 years ago
15

Key Event 1: Chemical energy is invested. Key Event 2: High-energy electrons stored in bonds are released and transferred with p

rotons to available electron carriers. Key Event 3: ATP is made by phosphorylation. During glycolysis, how many NADH molecules are produced per glucose molecule? Two Four One
Chemistry
1 answer:
Maslowich3 years ago
7 0

Answer:

During Glycolysis 2 molecules of NADH are formed.

Explanation:

When the glycolytic intermediate glyceraldehyde-3-phosphate is converted to 1,3-bisphosphoglycerate by the catalytic activity of glyceraldehyde -3-phosphate dehydrogenase at that time 2 molecules of NAD+ undergo reduction to form 2 molecules of NADH.

   The so formed NADH enters into the electron transport chain to generate ATP.

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CaC12 * 3H20 is correctly named
ki77a [65]

Answer:

calcium chloride deihydrate

4 0
3 years ago
What is the molarity when 0.181 moles of MgNO3)2 are dissolved in enough water to make 0.750 L solution?
eimsori [14]

Answer:

Molarity = 0.24 M

Explanation:

Given data:

Number of moles of Mg(NO₃)₂ = 0.181 mol

Volume of solution = 0.750 L

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

by putting values,

Molarity = 0.181 mol / 0.750 L

Molarity = 0.24 M

4 0
3 years ago
How do I do letter D? Someone help me please
Minchanka [31]
So for D you have to find energy right
from c you get wavelength Lambda
so on D use this
E = Hc / lambda
c is given 1.5 x 10 ^20
h = 6.624 x 10^-34
and then you get answer for energy
8 0
3 years ago
Sodium combines with water to produce sodium hydroxide and hydrogen gas. Which word equation represents this violent reaction?
zzz [600]
A coupleword to describe the action could be, Berserk, destructive, furious, unrestrained, impetuous, intemperate and uncontrollable
5 0
3 years ago
Denver, Colorado (altitude above sea level is 5,280 ft) has an atmospheric pressure of 633. mm Hg. Calculate the boiling point o
Fed [463]

Answer:

T2 = 94.6 C

Explanation:

Use Clausius-Clayperyon equation.

ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K

P1 = 760 mmHg

P2 = 630 mmHg  

T1 = 373 K

T2 = ?

∆Hvap = 40.7 kJ/mole

R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)

Plug in and solve for T2

ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)

T2 = 367.74 K = 94.6 C

8 0
3 years ago
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