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NARA [144]
2 years ago
5

The length of one side of a parallelogram is 3 more than twice the length of the adjacent side.

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

2x + 3

Step-by-step explanation:

Let the length of the adjacent side = x.

The length of the side then is:

2x + 3

You might be interested in
Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobil
o-na [289]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobile. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $120 and a sample of 23 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. Let 4 year old automobiles be represented by population 1.

State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles.

At a 0.01 level of significance, what is your conclusion? What is the p-value?

Answer:

Null hypotheses = H₀ = σ₁² ≤ σ₂²

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic = 1.44

p-value = 0.1954

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

Step-by-step explanation:

Let σ₁² denotes the variance of 4 years old automobiles

Let σ₂² denotes the variance of 2 years old automobiles

State the null and alternative hypotheses:

The null hypothesis assumes that the variance in annual repair costs is smaller for older automobiles.

Null hypotheses = H₀ = σ₁² ≤ σ₂²

The alternate hypothesis assumes that the variance in annual repair costs is larger for older automobiles.

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic:

The test statistic is given by

Test statistic = σ₁²/σ₂²

Test statistic = 120²/100²

Test statistic = 1.44

p-value:

The degree of freedom corresponding to 4 years old automobiles is given by

df₁ = n - 1  

df₁ = 26 - 1  

df₁ = 25

The degree of freedom corresponding to 2 years old automobiles is given by

df₂ = n - 1  

df₂ = 23 - 1  

df₂ = 22

Using Excel to find out the p-value,  

p-value = FDIST(F-value, df₁, df₂)

p-value = FDIST(1.44, 25, 22)

p-value = 0.1954

Conclusion:

When the p-value is less than the significance level then we reject the Null hypotheses

p-value < α   (reject H₀)

But for the given case,

p-value > α

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

8 0
3 years ago
Any one can help me please please I need help please each one 3 step explanation
Art [367]

Answer:

a) Area of wall to be painted = 114 sq ft

b) Number of cans required = 2×5 = 10

c) Total cost of paint = $338.43

Step-by-step explanation:

<h2>Part a)</h2>

We are asked to find the area of wall that needs to be painted.

we need to subtract the area of window from the area of wall.

We know that area of a rectangular shape is given by

Area = Width×Length

Area of whole wall = 8×15 = 120 sq ft

Area of window = 2×3 = 6 sq ft

Area of wall to be painted = 120 - 6 = 114 sq ft

<h2>Part b)</h2>

1 can of paint will cover 25 sq ft of area.

So to cover the area of wall to be painted,

114/25 = 4.56

since number of cans cannot be in fraction so we would need 5 cans

Since two coats of paints are needed so

Number of cans required = 2×5 = 10

<h2>Part c)</h2>

1 can of paint costs $29.95

We have total 10 cans

$29.95×10 = $299.5

There is also a 13% tax so the total cost is

$299.5×0.13 = $38.93

Total cost of paint = $299.5 + $38.93

Total cost of paint = $338.43

3 0
3 years ago
Dequan is training for a marathon. He runs 20 miles every 4 days. What is the unit rate for Dequan?
KonstantinChe [14]

Answer:

Dequan walks 5 miles per day.

Step-by-step explanation:

So solve this problem, we just need to divide 20 miles by 4 days.

20 ÷ 4 = 5

Therefore, Dequan walks 5 miles per day.

Hope this helps! :D

5 0
2 years ago
Read 2 more answers
Where can u place these at tell me
Alex777 [14]
The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2

Hope this helps :)
5 0
3 years ago
Which basic calculation or process in mathematics relates to factors?
pav-90 [236]
Division and multiplication
7 0
2 years ago
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