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andrew-mc [135]
4 years ago
6

1. Accelerating objects are objects that are changing their velocity. Name the three controls on anautomobile that cause it to a

ccelerate.
Physics
1 answer:
Kay [80]4 years ago
3 0
Velocity is speed and its direction. Acceleration is any change of speed or direction. The gas pedal, the brake pedal, and the steering wheel can all cause that change.
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Elements produce their spectrum when their electrons _____.
Aleonysh [2.5K]
The correct answer is the third one: move toward the ground state. Remember please that Elements produce their spectrum when their electrons move toward the ground state. Hope this is very useful
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4 years ago
Which of the following is a contact force?
shusha [124]

hope this helps.........

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3 years ago
What is the measure of how much a material resists the formation of an electric field?
shusha [124]
The answer is c capacitance
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4 years ago
A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force
alukav5142 [94]

Answer:

497.6 N

Explanation:

From the question,

The net force on the skydiver = weight of the skydiver- the resistive force of air

F' = W-F...................... Equation 1

Where W = weight of the skydiver, F = resistive force of air.

But,

W = mg................ Equation 2

Where m = mass of the skydiver, g = acceleration due to gravity.

Substitute equation 2 into equation 1

F' = mg-F............ Equation 3

Given: m = 87 kg, F = 355 N, g = 9.8 m/s²

Substitute these values into equation 3

F' = 87(9.8)-355

F' = 852.6-355

F' = 487.6 N

6 0
3 years ago
Read 2 more answers
On a cold winter day when the temperature is −20∘C, what amount of heat is needed to warm to body temperature (37 ∘C) the 0.50 L
vlabodo [156]

Answer:

75.6J

Explanation:

Hi!

To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,

Given the above we have the following equation.

Q=(m)(h2)-(m)(h1)

where

m=mass=1.3×10−3kg.

h2= entalpy at 37C

h1= entalpy at -20C

Q=m(h2-h1)

remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference

Q=mCp(T2-T1)

Cp= specific heat of air = 1020 J/kg⋅K

Q=(1.3×10−3)(1020)(37-(-20))=75.6J

4 0
3 years ago
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