Answer:
increases by a factor of 
Explanation:
First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:

where v = 0 m/s is the final velocity of the package when it stops,
is the initial velocity of the package when it, a is the deceleration, and
is the distance traveled.
So the equation above can be simplified and plug in Δs = d,
for the 1st case
(1)
For the 2nd scenario where the ramp is changed and distance becomes 2d, 
(2)
let equation (2) divided by (1) we have:



So the initial speed increases by
. If the deceleration a stays the same and time is the ratio of speed over acceleration a

The time would increase by a factor of 
A.draw in the forces .Use the scale 1cm =10n of force
Answer:

Explanation:
Given:
height above which the rock is thrown up, 
initial velocity of projection, 
let the gravity on the other planet be g'
The time taken by the rock to reach the top height on the exoplanet:
where:
final velocity at the top height = 0 
(-ve sign to indicate that acceleration acts opposite to the velocity)

The time taken by the rock to reach the top height on the earth:



Height reached by the rock above the point of throwing on the exoplanet:

where:
final velocity at the top height = 0 


Height reached by the rock above the point of throwing on the earth:



The time taken by the rock to fall from the highest point to the ground on the exoplanet:
(during falling it falls below the cliff)
here:
initial velocity= 0 



Similarly on earth:

Now the required time difference:


You can use the formula A=F/M, the rate that it is being accelerated upward is 3.3, so about 3.
The mass of the basket = weight/acceleration due to gravity. (75/10=7.5 kg)
100 (upward force from girl) minus 75 (downward force from basket) is 25.
So 25=7.5a, which becomes 25/7.5, which equals 3.33 kg x m/s.
And when rounded, the momentum is about 3, (or 3 p).
Hope this helps!