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Veronika [31]
4 years ago
5

What is the measure of how much a material resists the formation of an electric field?

Physics
1 answer:
shusha [124]4 years ago
5 0
The answer is c capacitance
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a charge Q exerts a 2.4 N force on another charge q.If the distance between the charges is doubled,what is the magnitude of the
GrogVix [38]
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3 years ago
Its important please answer ​
Yuri [45]

Answer: Well we see that v= u- ft/m

lets say that ft= feet and m= mass

so you divide those and subtract u

leaving you with the value of v which is 13

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3 years ago
If Earth were replaced by an object with the same mass but much smaller in size, would the moon continue to orbit the new object
Tanzania [10]
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3 0
4 years ago
Read 2 more answers
Find the area under the standard normal curve between z=0.19 and z=2.18. round your answer to four decimal places, if necessary.
LiRa [457]

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

<h3>How can we calculate the area under the curve?</h3>

To calculate the The area under the standard normal curve  between z=0.19 and z=2.18, we are using two things,

<u>Step 1</u>: The formula,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.

Now we put the known values from the picture in the above formula, we get,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

Or, P(0.19<z<2.18)=  0.9854-0.5753

Or, P(0.19<z<2.18)=  0.4101

From the above calculation we can easily conclude that,

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

Learn more about the standard normal curve:

brainly.com/question/17088387

#SPJ4

5 0
2 years ago
A 1.4kg block and a 2.7kg block are attached to opposite ends of a light rope. The rope hangs over a solid, frictionless pulley
leonid [27]

Answer:

32.67 m/s^2

Explanation:

27 cm = 0.27 m

As the blocks are hanging on 2 sides of the pulley, their difference in mass would generate a net force toward the heavier side:

Let g = 9.81 m/s2

F = g(2.7 - 1.4) = 9.81*1.3 = 12.753 N

This force would generate a torque at 0.27 m moment arm

T = F*r = 12.753*0.27 = 3.44 Nm

The moment of inertia of the solid disk:

I = mR^2/2

Where m = 0.78 kg is the disk mass and R = 0.27 m is the radius of the disk.

I = 0.780*27^2/2 = 0.028431 kgm^2

So the angular acceleration of the torque is

\alpha = T/I = 3.44 / 0.028431 = 121 rad/s^2

So the linear acceleration is its angular component times radius

a = \alpha r = 121 * 0.27 = 32.67 m/s^2

3 0
3 years ago
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