Question

100 POINTS FOR THE ACTUAL RIGHT ANSWER There are 122 cats and dogs. the amount of dogs is 5 more than 2 times the number of cats. How many cats and dogs are there. Give an algebraic equation
I need the algebraic equation and answer for the # of cats and dogs

Answer 1

Answer:

• There are 39 cats and 83 dogs.

Step-by-step explanation:

We know that:

• D + C = 122
• D = 5 + 2C
• C = Number of cats
• D = Number of dogs

Work:

• D + C = 122
• => 5 + 2C + C = 122
• => 5 + 3C = 122
• => 3C = 122 - 5
• => 3C = 117
• => C = 117/3
• => $\hug\boxed{C =39}$
• => D + C = 122
• => D + 39 = 122
• => D = 122 - 39
• => $\hug\boxed{D = 8 3}$

Hence, there are 39 cats and 83 dogs.

Hoped this helped.

$BrainiacUser1357$

Answer 2

Answer:

d + c = 122

d - 5 = 2c

so same as saying

2d + 2c = 244

we plug in for 2c

2d + d - 5 = 244

2d + d = 249

3d = 249

d = 249 / 3

d = 83

since d - 5 = 2c

83 - 5 = 2c

78 = 2c

c = 39

there are 39 cats and 83 dogs

39 + 83 = 122

Step-by-step explanation: